Easy riddles

cleanfunny

An orange

What does the orange do, when it takes a test?
It concentrates.
86.91 %
43 votes

funnyshort

Against the law

Why is it against the law for a man living in Delhi to be buried in Mumbai?
Because he is still living.
86.91 %
43 votes

animalcleanfunny

Swimming in the ocean

If you were swimming in the ocean and a big alligator attacked you, what should you do?
Nothing. There are no alligators in the ocean.
86.91 %
43 votes

logicshort

Two baseball teams

Two baseball teams played a game. One team won but no man touched base. How could that be?
They were all girl teams.
86.91 %
43 votes

logicshort

Country hidden in the paragraph

What country is hidden in the paragraph below? As defendants, we deny all involvement in the unscrupulous dealings which have come to light in the recent government investigation.
Sweden.
86.91 %
43 votes

cleanfunnyshort

Barrel

A man takes a barrel that weighs 20 pounds and puts something in it. It now weighs less than 20 pounds. What did he put in the barrel?
He put a hole in the barrel to make it weigh less.
86.91 %
43 votes

logicmath

2 Player and N Coin – Strategy Puzzle

There are n coins in a line. (Assume n is even). Two players take turns to take a coin from one of the ends of the line until there are no more coins left. The player with the larger amount of money wins. Would you rather go first or second? Does it matter? Assume that you go first, describe an algorithm to compute the maximum amount of money you can win. Note that the strategy to pick maximum of two corners may not work. In the following example, first player looses the game when he/she uses strategy to pick maximum of two corners. Example 18 20 15 30 10 14 First Player picks 18, now row of coins is 20 15 30 10 14 Second player picks 20, now row of coins is 15 30 10 14 First Player picks 15, now row of coins is 30 10 14 Second player picks 30, now row of coins is 10 14 First Player picks 14, now row of coins is 10 Second player picks 10, game over. The total value collected by second player is more (20 + 30 + 10) compared to first player (18 + 15 + 14). So the second player wins.
Going first will guarantee that you will not lose. By following the strategy below, you will always win the game (or get a possible tie). (1) Count the sum of all coins that are odd-numbered. (Call this X) (2) Count the sum of all coins that are even-numbered. (Call this Y) (3) If X > Y, take the left-most coin first. Choose all odd-numbered coins in subsequent moves. (4) If X < Y, take the right-most coin first. Choose all even-numbered coins in subsequent moves. (5) If X == Y, you will guarantee to get a tie if you stick with taking only even-numbered/odd-numbered coins. You might be wondering how you can always choose odd-numbered/even-numbered coins. Let me illustrate this using an example where you have 6 coins: Example 18 20 15 30 10 14 Sum of odd coins = 18 + 15 + 10 = 43 Sum of even coins = 20 + 30 + 14 = 64. Since the sum of even coins is more, the first player decides to collect all even coins. He first picks 14, now the other player can only pick a coin (10 or 18). Whichever is picked the other player, the first player again gets an opportunity to pick an even coin and block all even coins.
86.91 %
43 votes